Chem 104 lab Study guides, Class notes & Summaries

CHEM 104 Experiment 4: Molarity of Vitamin C - Portage Learning Purpose: The purpose of this lab is to determine a better understand of solutions and concentrations relating to vitamins, specifically vitamin C or ascorbic acid. In order to do so, we measured the vitamin C in a few different fruits to determine the concertation of vitamin c in each. Procedure: Part 1: Determining the vitamin c concentration of iodine 1. Iodine was placed in a buret. 2. A solution was made from the commercial vit...

CHEM 104 Experiment 7 Organic Synthesis - Portage Learning Purpose: The purpose of this lab was to determine the process of synthesizing various carboncontaining organic products including aspirin, urea, & salicylic acid. In doing so, we were also able to calculate the percent yield in each of these experiments. Procedure: Part 1: Synthesis of aspirin 1. Placed 2.0 g of salicylic acid & placed it in a flask 2. 5.0 mL of acetic anhydride was then added to the flask & mixed 3. 5 drops of sulfuric...

Portage Learning Chem 104: M6 Exam- Requires Respondus LockDown Browser: General Chemistry 2 with Lab

1. For lower premolars, the purpose of inclining the handpiece lingually is to, A. Avoid buccal pulp horn B. Avoid lingual pulp horn C. Remove unsupported enamel D. Conserve lingual dentine - ANSWER A. Avoid buccal pulp horn Explanation 1- avoid BUCCAL pulp horn 2- conserve ling. dentine So take A and B if available 2. For an amalgam restoration of a weakened cusp you should, A. reduce cusp by 2mm on a flat base for more resistance B. reduce cusp by 2mm following the outli...

CHEM 104: Module 1 Exam General Chemistry II with Lab Exams – 2022- Portage Learning

Portage Learning CHEM 104 Module 2: Problem Set: General Chemistry 2 with Lab

Portage Learning CHEM 104 Module 4: Problem Set: General Chemistry 2 with Lab

Portage Learning CHEM 104 Module 1: Problem Set: General Chemistry 2 with Lab

Portage Learning CHEM 104 Module 5: Problem Set 1: General Chemistry 2 with Lab

CHEM 102 Winter 18 Final Exam (A) Questions and Answers Potentially useful data: x  1 atm = 760 torr = 760 mm Hg 2 a [A]t = – kt + [A]o ΔG° = ΔH° – T ΔS° ln[A]t = – kt + ln[A]o ΔG = ΔG° + RT ln Q 1/[A]t = kt +1/[A]o ΔG° = – RT ln K First order half-life: t1/2 = ln2 / k ΔG° = – nFE° pH  pKa  log base acid  E  E  R T ln Q n F R = 8.314 J mol-1 K-1 F = 96500 C/mol e- 1. Please choose the letter “A” as your a...